What is the domain of f(x)=(1/3)^x+1 ?

The domain of f(x)=(1/3)^x+1 is -infinity <x<infinity

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domain of f(x)=(1/3)^x+1

domain

f (x) = (\frac{1}{3})^{x} + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{9 x - 4}{4 x + 8}

(x^{2} + 2 x - 1) \cdot (2 x^{2} - 3 x + 6)

f (x) = \frac{( x - 4 )}{( x + 5 )}

f (x) = \frac{2}{3} x - 12

\frac{x + 4}{- 4 x + 3}

What is the domain of f(x)=(1/3)^x+1 ?
The domain of f(x)=(1/3)^x+1 is -infinity <x<infinity