What is the domain of f(x)=sqrt(4+3x-x^2) ?

The domain of f(x)=sqrt(4+3x-x^2) is -1<= x<= 4

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domain of f(x)=sqrt(4+3x-x^2)

domain

f (x) = 4 + 3 x - x^{2}

- 1 \leq x \leq 4

Interval Notation

[- 1, 4]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 4

The function domain

- 1 \leq x \leq 4

f (x) = 5 - x^{3}

\frac{x - 7}{x + 12}

2 π r^{2} + 16 π r

f (x) = - 4 x + 10

\frac{5 - x}{- 4 x + 8}

What is the domain of f(x)=sqrt(4+3x-x^2) ?
The domain of f(x)=sqrt(4+3x-x^2) is -1<= x<= 4