What is the domain of 2/(1-cos(x)) ?

The domain of 2/(1-cos(x)) is 2pin<x<2pi+2pin

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domain of 2/(1-cos(x))

domain

\frac{2}{1 - cos ( x )}

2 πn < x < 2 π + 2 πn

Interval Notation

(2 πn, 2 π + 2 πn)

Solution steps

Take the denominator(s) of

\frac{2}{1 - cos ( x )}

and compare to zero:

x = 2 πn

Periodicity of

\frac{2}{1 - cos ( x )} : 2 π

Combine period:

2 πn \leq x < 2 π + 2 πn

and undefined points.

The domain is

2 πn < x < 2 π + 2 πn

f (x) = \frac{- x + 10}{x ^{3}}

f (x) = \frac{x ^{2}}{ln ( x )}

(\frac{1}{x - 7}) + (\frac{1}{x} - 9)

f (x) = 25 - 5^{x}

f (x) = \frac{x ^{3}}{( x - 1 ) ^{2}}

What is the domain of 2/(1-cos(x)) ?
The domain of 2/(1-cos(x)) is 2pin<x<2pi+2pin