What is the domain of f(x)= 2/(sqrt(-x^2+4x+5)) ?

The domain of f(x)= 2/(sqrt(-x^2+4x+5)) is -1<x<5

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domain of f(x)= 2/(sqrt(-x^2+4x+5))

domain

f (x) = \frac{2}{- x ^{2} + 4 x + 5}

- 1 < x < 5

Interval Notation

(- 1, 5)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 5

Find undefined (singularity) points:

x = - 1, x = 5

Combine real regions and undefined points for final function domain

- 1 < x < 5

f (x) = \frac{x}{8}

f (x) = 22 x - 1694

f (x) = 5 x^{4} - 3 x^{2} + 7

f (x) = lo g_{\frac{2}{5}} (x)

tan (3 x - 5)

What is the domain of f(x)= 2/(sqrt(-x^2+4x+5)) ?
The domain of f(x)= 2/(sqrt(-x^2+4x+5)) is -1<x<5