What is the domain of f(x)=(sqrt(1-x^2))^x ?

The domain of f(x)=(sqrt(1-x^2))^x is -1<x<= 1

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domain of f(x)=(sqrt(1-x^2))^x

domain

f (x) = (1 - x^{2})^{x}

- 1 < x \leq 1

Interval Notation

(- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Check exponents domain:

- 1 < x \leq 1

Combine real regions and undefined points for final function domain

- 1 < x \leq 1

f (x) = 2 x - 3 + 5

\frac{x + 10}{x - 5}

6 x^{2} + 500 x + 8000

f (x) = arccos (e^{3 x})

f (x) = \frac{1}{x ^{3} + 1}

What is the domain of f(x)=(sqrt(1-x^2))^x ?
The domain of f(x)=(sqrt(1-x^2))^x is -1<x<= 1