What is the domain of f(x)=sqrt(8x+32) ?

The domain of f(x)=sqrt(8x+32) is x>=-4

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domain of f(x)=sqrt(8x+32)

domain

f (x) = 8 x + 32

x \geq - 4

Interval Notation

[- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

The function domain

x \geq - 4

f (x) = \frac{2 x + 3}{3 x - 4}

lo g_{3} (x^{2})

f (x) = \frac{x}{ln ( x - 1 ) - 1}

y = 4 csc (x - \frac{π}{6}) + 5

f (x) = 20 x - 1740

What is the domain of f(x)=sqrt(8x+32) ?
The domain of f(x)=sqrt(8x+32) is x>=-4