What is the domain of f(x)=\sqrt[3]{y+2} ?

The domain of f(x)=\sqrt[3]{y+2} is -infinity <y<infinity

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domain of f(x)=\sqrt[3]{y+2}

domain

- \infty < y < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < y < \infty

f (x) = 2 x^{2} - 4 x - 1

ln (u)

f (x) = \frac{1}{2} tan (x)

f (x) = \frac{2 x ^{2}}{6 x ^{2} - x - 2}

f (x) = 5 - 2 x + 4

What is the domain of f(x)=\sqrt[3]{y+2} ?
The domain of f(x)=\sqrt[3]{y+2} is -infinity <y<infinity