What is the domain of f(x)=sqrt(x-4x^3) ?

The domain of f(x)=sqrt(x-4x^3) is x<=-1/2 \lor 0<= x<= 1/2

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domain of f(x)=sqrt(x-4x^3)

domain

f (x) = x - 4 x^{3}

x \leq - \frac{1}{2} or 0 \leq x \leq \frac{1}{2}

Interval Notation

(- \infty, - \frac{1}{2}] \cup [0, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

x \leq - \frac{1}{2} or 0 \leq x \leq \frac{1}{2}

The function domain

x \leq - \frac{1}{2} or 0 \leq x \leq \frac{1}{2}

f (x) = \frac{( 4 x + 3 )}{( 2 x - 1 )}

f (x) = x^{2} + 4 x

f (x) = \frac{2 x - 7}{3}

\frac{2}{3} x - 12

e^{2 x} - 3

What is the domain of f(x)=sqrt(x-4x^3) ?
The domain of f(x)=sqrt(x-4x^3) is x<=-1/2 \lor 0<= x<= 1/2