What is the domain of f(x)=sqrt(sin(2x)) ?

The domain of f(x)=sqrt(sin(2x)) is pin<= x<= pi/2+pin

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domain of f(x)=sqrt(sin(2x))

domain

f (x) = sin (2 x)

πn \leq x \leq \frac{π}{2} + πn

Interval Notation

[πn, \frac{π}{2} + πn]

Solution steps

Find non-negative values for radicals:

πn \leq x \leq \frac{π}{2} + πn

The function domain

πn \leq x \leq \frac{π}{2} + πn

f (x) = 6 x - 1248

\frac{2 x - 6}{5}

f (x) = \frac{x - 3}{2 x - 7}

12 x - 2148

f (x) = \frac{3 x + 2}{2 x - 5}

What is the domain of f(x)=sqrt(sin(2x)) ?
The domain of f(x)=sqrt(sin(2x)) is pin<= x<= pi/2+pin