What is the domain of f(x)=sqrt(9x-x^3) ?

The domain of f(x)=sqrt(9x-x^3) is x<=-3\lor 0<= x<= 3

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domain of f(x)=sqrt(9x-x^3)

domain

f (x) = 9 x - x^{3}

x \leq - 3 or 0 \leq x \leq 3

Interval Notation

(- \infty, - 3] \cup [0, 3]

Solution steps

Find non-negative values for radicals:

x \leq - 3 or 0 \leq x \leq 3

The function domain

x \leq - 3 or 0 \leq x \leq 3

f (x) = \frac{x ^{2}}{4 - x ^{2}}

12 x^{3} - 5 x^{2} - 11 x + 6

f (x) = x ln (x^{2})

f (x) = 12 + lo g_{10} (1 - x^{2})

f (x) = \frac{2 x + 3}{x - 7}

What is the domain of f(x)=sqrt(9x-x^3) ?
The domain of f(x)=sqrt(9x-x^3) is x<=-3\lor 0<= x<= 3