What is the domain of y=(sqrt(2x+14))/(x^2-49) ?

The domain of y=(sqrt(2x+14))/(x^2-49) is -7 7

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domain of y=(sqrt(2x+14))/(x^2-49)

domain

y = \frac{2 x + 14}{x ^{2} - 49}

- 7 < x < 7 or x > 7

Interval Notation

(- 7, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 7

Find undefined (singularity) points:

x = 7, x = - 7

Combine real regions and undefined points for final function domain

- 7 < x < 7 or x > 7

f (x) = \frac{x + 1}{x ^{2} - x - 2}

f (x) = \frac{x + 6}{x ^{2} - 4}

(x - 1)^{3}

f (x) = \frac{ln ( x + 5 )}{x ^{2} - 2 x - 3}

h (x) = x^{2} + 16

What is the domain of y=(sqrt(2x+14))/(x^2-49) ?
The domain of y=(sqrt(2x+14))/(x^2-49) is -7<x<7\lor x>7