What is the domain of y=(x-5)/(x^2-4x) ?

The domain of y=(x-5)/(x^2-4x) is x 4

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domain of y=(x-5)/(x^2-4x)

domain

y = \frac{x - 5}{x ^{2} - 4 x}

x < 0 or 0 < x < 4 or x > 4

Interval Notation

(- \infty, 0) \cup (0, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = 0

The function domain

x < 0 or 0 < x < 4 or x > 4

f (x) = \frac{4 x}{5 ( x - 1 ) ( x - 6 )}

y = 3 - 2 x

f (x) = 3 x^{2} + 8 x - 1

f (x) = \frac{x + 6}{( x - 6 ) ( x - 1 )}

2 x + 3, - 2 \leq x < 1

What is the domain of y=(x-5)/(x^2-4x) ?
The domain of y=(x-5)/(x^2-4x) is x<0\lor 0<x<4\lor x>4