What is the domain of f(x)=sqrt(6-x)+\sqrt[4]{x-2} ?

The domain of f(x)=sqrt(6-x)+\sqrt[4]{x-2} is 2<= x<= 6

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domain of f(x)=sqrt(6-x)+\sqrt[4]{x-2}

domain

2 \leq x \leq 6

Interval Notation

[2, 6]

Solution steps

Find non-negative values for radicals:

2 \leq x \leq 6

The function domain

2 \leq x \leq 6

f (x) = \frac{( 4 x ^{2} + 4 )}{( 2 x ^{2} - 8 )}

y = \frac{x + 3}{12 - x ^{2} - 25}

f (x) = \frac{x - 1}{x ^{2} - 1}

f (x) = lo g_{10} (∣ x ∣)

f (x) = \frac{3 x + 2}{x ^{2} - 4}

What is the domain of f(x)=sqrt(6-x)+\sqrt[4]{x-2} ?
The domain of f(x)=sqrt(6-x)+\sqrt[4]{x-2} is 2<= x<= 6