What is the domain of g(x)= 1/(sqrt(x-9)) ?

The domain of g(x)= 1/(sqrt(x-9)) is x>9

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domain of g(x)= 1/(sqrt(x-9))

domain

g (x) = \frac{1}{x - 9}

x > 9

Interval Notation

(9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x > 9

f (x) = - (x + 2)^{5} (x - 4)^{4}

f (x) = x^{4} - 2 x^{2} + 3

f (x) = \frac{3 - x}{∣ 2 x - 5 ∣}

f (t) = t

What is the domain of g(x)= 1/(sqrt(x-9)) ?
The domain of g(x)= 1/(sqrt(x-9)) is x>9