What is the domain of f(x)=sqrt((x-1)(x+2)) ?

The domain of f(x)=sqrt((x-1)(x+2)) is x = 1

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domain of f(x)=sqrt((x-1)(x+2))

domain

f (x) = (x - 1) (x + 2)

x \leq - 2 or x \geq 1

Interval Notation

(- \infty, - 2] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 1

The function domain

x \leq - 2 or x \geq 1

y = x - 5 - 1

f (x) = \frac{2}{1 + x}

f (x) = - x^{2} + 16

3^{x + 3}

f (x) = \frac{( 2 x - 6 )}{5}

What is the domain of f(x)=sqrt((x-1)(x+2)) ?
The domain of f(x)=sqrt((x-1)(x+2)) is x<=-2\lor x>= 1