What is the domain of f(x)=log_{2}(x-3)+1 ?

The domain of f(x)=log_{2}(x-3)+1 is x>3

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domain of f(x)=log_{2}(x-3)+1

domain

f (x) = lo g_{2} (x - 3) + 1

x > 3

Interval Notation

(3, \infty)

Solution steps

Find positive values for logs:

x > 3

The function domain

x > 3

f (x) = f (x) = \frac{( x ^{2} + 16 )}{( x ^{2} - 9 )}

f (x) = \frac{1}{4} x

f (x) = x - 1 - 1

f (x) = 75 x

f (x) = \frac{3 x}{2 x - 1}

What is the domain of f(x)=log_{2}(x-3)+1 ?
The domain of f(x)=log_{2}(x-3)+1 is x>3