What is the domain of f(x)=(x+1)^{1/2}+2 ?

The domain of f(x)=(x+1)^{1/2}+2 is x>=-1

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domain of f(x)=(x+1)^{1/2}+2

domain

f (x) = (x + 1)^{\frac{1}{2}} + 2

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = \frac{x ^{2}}{1 - x ^{2}}

\frac{3 x - 2}{5 - 2 x}

f (x) = x - 5 + 3

f (x) = \frac{7}{4 x + 2}

f (x) = x - 11

What is the domain of f(x)=(x+1)^{1/2}+2 ?
The domain of f(x)=(x+1)^{1/2}+2 is x>=-1