What is the domain of y=((x^2-16))/((x^2-x-6)) ?

The domain of y=((x^2-16))/((x^2-x-6)) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=((x^2-16))/((x^2-x-6))

domain

y = \frac{( x ^{2} - 16 )}{( x ^{2} - x - 6 )}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

f (x) = - x^{2} + x

f (x) = \frac{2 x}{x ^{3} - x ^{2} - 2 x}

f (x) = \frac{x ^{2} - 4 x + 4}{x - 2}

f (x) = \frac{x ^{2}}{( x - 2 ) ^{2}}

f (x) = \frac{2}{3} x - 12, - 6 \leq x \leq 4

What is the domain of y=((x^2-16))/((x^2-x-6)) ?
The domain of y=((x^2-16))/((x^2-x-6)) is x<-2\lor-2<x<3\lor x>3