What is the domain of f(x)=sqrt(3x+2)+1 ?

The domain of f(x)=sqrt(3x+2)+1 is x>=-2/3

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domain of f(x)=sqrt(3x+2)+1

domain

f (x) = 3 x + 2 + 1

x \geq - \frac{2}{3}

Interval Notation

[- \frac{2}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{2}{3}

The function domain

x \geq - \frac{2}{3}

f (x) = (x + 3)^{2} - 4

f (x) = 2 x^{2} - x

y = 160 + 40 x

f (x) = \frac{( 8 x + 5 )}{( 2 - 5 x )}

y = 3^{x + 5}

What is the domain of f(x)=sqrt(3x+2)+1 ?
The domain of f(x)=sqrt(3x+2)+1 is x>=-2/3