What is the domain of f(x)=(x^2-4x+3)/(x^2-1) ?

The domain of f(x)=(x^2-4x+3)/(x^2-1) is x 1

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domain of f(x)=(x^2-4x+3)/(x^2-1)

domain

f (x) = \frac{x ^{2} - 4 x + 3}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

x^{2} + 16

f (x) = \frac{- 1}{x ^{2} - 36}

f (x) = - 2 x^{2} + 4 x - 3

f (x) = \frac{( - 1 )}{( x ^{2} - 36 )}

f (x) = \frac{6 x - 1}{10 x + 4}

What is the domain of f(x)=(x^2-4x+3)/(x^2-1) ?
The domain of f(x)=(x^2-4x+3)/(x^2-1) is x<-1\lor-1<x<1\lor x>1