What is the domain of sqrt(x^2-x-6) ?

The domain of sqrt(x^2-x-6) is x = 3

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domain of sqrt(x^2-x-6)

domain

x^{2} - x - 6

x \leq - 2 or x \geq 3

Interval Notation

(- \infty, - 2] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 3

The function domain

x \leq - 2 or x \geq 3

- (x + 2)^{5} (x - 4)^{4}

b^{x}

y = (x + 2)^{\frac{1}{4}}

f (x) = arccos (ln (3 x))

f (x) = \frac{6}{x ^{2} - 2 x}

What is the domain of sqrt(x^2-x-6) ?
The domain of sqrt(x^2-x-6) is x<=-2\lor x>= 3