What is the domain of log_{1/5}(x^2-x-12)+6 ?

The domain of log_{1/5}(x^2-x-12)+6 is x 4

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domain of log_{1/5}(x^2-x-12)+6

domain

lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6

x < - 3 or x > 4

Interval Notation

(- \infty, - 3) \cup (4, \infty)

Solution steps

Find positive values for logs:

x < - 3 or x > 4

The function domain

x < - 3 or x > 4

f (x) = \frac{( 2 - x )}{x ^{2} - x - 6}

f (x) = ln (e^{x} + 3)

\frac{2 x - 4}{14 x ^{2} - 3 x - 5}

f (x) = ln (x^{2} - 10 x)

g (x) = x + 2

What is the domain of log_{1/5}(x^2-x-12)+6 ?
The domain of log_{1/5}(x^2-x-12)+6 is x<-3\lor x>4