What is the domain of f(x)= 2/3+(sqrt(4-x^2))/(x-3) ?

The domain of f(x)= 2/3+(sqrt(4-x^2))/(x-3) is -2<= x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 2/3+(sqrt(4-x^2))/(x-3)

domain

f (x) = \frac{2}{3} + \frac{4 - x ^{2}}{x - 3}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 2 \leq x \leq 2

f (x) = \frac{7}{x + 1}

f (x) = 4 x^{2} + 12 x + 9

\frac{1}{2 x 3 + ln ( x )}

\frac{x ^{2} + 5 x + 6}{x ^{2} - 4}

f (x) = 3 - 2 x - 4

What is the domain of f(x)= 2/3+(sqrt(4-x^2))/(x-3) ?
The domain of f(x)= 2/3+(sqrt(4-x^2))/(x-3) is -2<= x<= 2