What is the domain of f(t)=sqrt(4-t^2) ?

The domain of f(t)=sqrt(4-t^2) is -2<= t<= 2

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domain of f(t)=sqrt(4-t^2)

domain

f (t) = 4 - t^{2}

- 2 \leq t \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq t \leq 2

The function domain

- 2 \leq t \leq 2

x^{2} - 4 x + 3

6 x - 6

f (x) = ∣ x ∣ + ∣ x - 1 ∣ + ∣ x - 2 ∣

f (x) = - 2 x + 8

f (x) = \frac{3}{x + 5}

What is the domain of f(t)=sqrt(4-t^2) ?
The domain of f(t)=sqrt(4-t^2) is -2<= t<= 2