What is the domain of y=sqrt(x^2-4x-5) ?

The domain of y=sqrt(x^2-4x-5) is x = 5

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domain of y=sqrt(x^2-4x-5)

domain

y = x^{2} - 4 x - 5

x \leq - 1 or x \geq 5

Interval Notation

(- \infty, - 1] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 5

The function domain

x \leq - 1 or x \geq 5

y = 2 x^{2} - 8 x + 8

5 \cdot (\frac{1}{4})^{x}

f (x) = \frac{x - 3}{3 x + 2}

f (x) = 2 - 0.4 x

f (x) = \frac{3 x - 5}{x}

What is the domain of y=sqrt(x^2-4x-5) ?
The domain of y=sqrt(x^2-4x-5) is x<=-1\lor x>= 5