What is the domain of f(x)= 1/(2x^2-8) ?

The domain of f(x)= 1/(2x^2-8) is x 2

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domain of f(x)= 1/(2x^2-8)

domain

f (x) = \frac{1}{2 x ^{2} - 8}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

\frac{x ^{2} - 8 x + 15}{x + 3}

- 4 x + 10

f (x) = 5 x^{6}

\frac{ln ( 2 x )}{x}

f (x) = \frac{1}{9 + x}

What is the domain of f(x)= 1/(2x^2-8) ?
The domain of f(x)= 1/(2x^2-8) is x<-2\lor-2<x<2\lor x>2