What is the domain of f(x)=2sqrt(x^2-9) ?

The domain of f(x)=2sqrt(x^2-9) is x = 3

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domain of f(x)=2sqrt(x^2-9)

domain

f (x) = 2 x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

f (x) = 2 x - 2 - 3

(x - 1) e^{- 2 x}

\frac{x}{1 + ∣ x ∣}

ln (x^{2} + 3 x)

f (x) = 7 x - x^{2}

What is the domain of f(x)=2sqrt(x^2-9) ?
The domain of f(x)=2sqrt(x^2-9) is x<=-3\lor x>= 3