What is the domain of f(x)= 1/(sqrt(-x^2+9x)) ?

The domain of f(x)= 1/(sqrt(-x^2+9x)) is 0<x<9

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domain of f(x)= 1/(sqrt(-x^2+9x))

domain

f (x) = \frac{1}{- x ^{2} + 9 x}

0 < x < 9

Interval Notation

(0, 9)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 9

Find undefined (singularity) points:

x = 0, x = 9

Combine real regions and undefined points for final function domain

0 < x < 9

- (x - 3)^{5} (x + 1)^{4}

sin (lo g_{10} (x))

f (x) = - lo g_{2} (3 (x - 2)) + 4

f (x) = x^{2} + 2 x - 7

f (x) = x^{2} + 2 x - 9

What is the domain of f(x)= 1/(sqrt(-x^2+9x)) ?
The domain of f(x)= 1/(sqrt(-x^2+9x)) is 0<x<9