What is the domain of f(x)=-1/2 (x+4)^2+8 ?

The domain of f(x)=-1/2 (x+4)^2+8 is -infinity <x<infinity

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domain of f(x)=-1/2 (x+4)^2+8

domain

f (x) = - \frac{1}{2} (x + 4)^{2} + 8

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{1}{3}

\frac{x - 4}{2 x + 2}

\frac{12 + x - x ^{2}}{∣ 2 x - 5 ∣}

f (x) = (x - 6) (x + 3)

- \frac{3}{x - 1}

What is the domain of f(x)=-1/2 (x+4)^2+8 ?
The domain of f(x)=-1/2 (x+4)^2+8 is -infinity <x<infinity