What is the domain of f(x)=(2x)/(sqrt(x^2-1)) ?

The domain of f(x)=(2x)/(sqrt(x^2-1)) is x 1

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domain of f(x)=(2x)/(sqrt(x^2-1))

domain

f (x) = \frac{2 x}{x ^{2} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

x^{2} y - 4 y + x = 0

f (x) = x^{3} - 9 x^{2} + 24 x - 7

f (x) = z

x^{2} + 2 x + 3

f (x) = \frac{x}{2} - 5

What is the domain of f(x)=(2x)/(sqrt(x^2-1)) ?
The domain of f(x)=(2x)/(sqrt(x^2-1)) is x<-1\lor x>1