What is the domain of f(x)=e^{1/x}sqrt(x^2+2x) ?

The domain of f(x)=e^{1/x}sqrt(x^2+2x) is x 0

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domain of f(x)=e^{1/x}sqrt(x^2+2x)

domain

f (x) = e^{\frac{1}{x}} x^{2} + 2 x

x \leq - 2 or x > 0

Interval Notation

(- \infty, - 2] \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 2 or x > 0

f (x) = \frac{3 x ^{2} + 9}{2 x ^{2} - 16}

f (x) = \frac{ln ( x + 5 )}{ln ( 2 )} + 3

f (x) = x - 3 + 5

\frac{x - 16}{2 ( x - 8 ) x - 8}

y = - 5 x + 2

What is the domain of f(x)=e^{1/x}sqrt(x^2+2x) ?
The domain of f(x)=e^{1/x}sqrt(x^2+2x) is x<=-2\lor x>0