What is the domain of f(x)=(sqrt(x+1))/(x^2) ?

The domain of f(x)=(sqrt(x+1))/(x^2) is -1 0

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domain of f(x)=(sqrt(x+1))/(x^2)

domain

f (x) = \frac{x + 1}{x ^{2}}

- 1 \leq x < 0 or x > 0

Interval Notation

[- 1, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or x > 0

g (x) = x - 1

g (x) = x + 3

f (x) = \frac{8}{x ^{2} - 1}

f (t) = cos (t)

f (x) = \frac{1}{x + 1 - 1}

What is the domain of f(x)=(sqrt(x+1))/(x^2) ?
The domain of f(x)=(sqrt(x+1))/(x^2) is -1<= x<0\lor x>0