What is the domain of y=(2x^3-5)/(x^2+x-6) ?

The domain of y=(2x^3-5)/(x^2+x-6) is x 2

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domain of y=(2x^3-5)/(x^2+x-6)

domain

y = \frac{2 x ^{3} - 5}{x ^{2} + x - 6}

x < - 3 or - 3 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3

The function domain

x < - 3 or - 3 < x < 2 or x > 2

\frac{1}{14 - 5 x - x ^{2}}

f (x) = \frac{2 x - 1}{5 - x}

\frac{1}{2} e^{- x} - 1

\frac{x ^{2} + 5 x + 6}{x ^{2} - 9}

f (x) = lo g_{10} (x^{2} + 2 x - 3)

What is the domain of y=(2x^3-5)/(x^2+x-6) ?
The domain of y=(2x^3-5)/(x^2+x-6) is x<-3\lor-3<x<2\lor x>2