What is the domain of (x/(2x^2-5))(sqrt(x)) ?

The domain of (x/(2x^2-5))(sqrt(x)) is 0 sqrt(5/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (x/(2x^2-5))(sqrt(x))

domain

(\frac{x}{2 x ^{2} - 5}) (x)

0 \leq x < \frac{5}{2} or x > \frac{5}{2}

Interval Notation

[0, \frac{5}{2}) \cup (\frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{5}{2}, x = - \frac{5}{2}

Combine real regions and undefined points for final function domain

0 \leq x < \frac{5}{2} or x > \frac{5}{2}

x^{2} + 2 x - 2

f (x) = \frac{2 x - 5}{7}

x^{3} - 8

y

f (x) = \frac{5}{2} + \frac{3}{2} x

What is the domain of (x/(2x^2-5))(sqrt(x)) ?
The domain of (x/(2x^2-5))(sqrt(x)) is 0<= x<sqrt(5/2)\lor x>sqrt(5/2)