What is the domain of f(x)=sqrt(x-2)+4 ?

The domain of f(x)=sqrt(x-2)+4 is x>= 2

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domain of f(x)=sqrt(x-2)+4

domain

f (x) = x - 2 + 4

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = \frac{2}{5} x - 3

f (x) = - \frac{2}{5}

f (x) = 3 6 - 3 x - 5 2 x + x

x y - y - x - 2 = 0

x - 1

What is the domain of f(x)=sqrt(x-2)+4 ?
The domain of f(x)=sqrt(x-2)+4 is x>= 2