What is the domain of f(x)=(x-13)/(sqrt(x^2-x-6)) ?

The domain of f(x)=(x-13)/(sqrt(x^2-x-6)) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x-13)/(sqrt(x^2-x-6))

domain

f (x) = \frac{x - 13}{x ^{2} - x - 6}

x < - 2 or x > 3

Interval Notation

(- \infty, - 2) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 3

Find undefined (singularity) points:

x = 3, x = - 2

Combine real regions and undefined points for final function domain

x < - 2 or x > 3

f (x) = e^{- 6 x}

\frac{1}{4} x

\frac{2 x}{x ^{2} - 9}

f (x) = 1 x^{3} + 4 x^{2} + 4 x + d

\frac{1}{x ^{3} + 1}

What is the domain of f(x)=(x-13)/(sqrt(x^2-x-6)) ?
The domain of f(x)=(x-13)/(sqrt(x^2-x-6)) is x<-2\lor x>3