What is the domain of (x^2)/(1+x) ?

The domain of (x^2)/(1+x) is x -1

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domain of (x^2)/(1+x)

domain

\frac{x ^{2}}{1 + x}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

y = \frac{5}{x + 2}

0.5 (x - 6)^{2} - 3

\frac{e ^{x}}{1 - e ^{2 x}}

y = \frac{x ^{2}}{x ^{2} - 4}

\frac{1}{x - 1 - 1}