What is the domain of f(x,y)= 1/(x^2) ?

The domain of f(x,y)= 1/(x^2) is x 0

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domain of f(x,y)= 1/(x^2)

domain

f (x, y) = \frac{1}{x ^{2}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

f (x) = 4^{x} - 1

f (x) = 2^{x + 4}

f (x) = - (x - 3)^{5} (x + 1)^{4}

f (x) = - (x - 4)^{2} + 16

f (x) = lo g_{10} (3 + 2 x - x^{2})

What is the domain of f(x,y)= 1/(x^2) ?
The domain of f(x,y)= 1/(x^2) is x<0\lor x>0