What is the domain of f(x)= 1/(sqrt(-x^2+6x)) ?

The domain of f(x)= 1/(sqrt(-x^2+6x)) is 0<x<6

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domain of f(x)= 1/(sqrt(-x^2+6x))

domain

f (x) = \frac{1}{- x ^{2} + 6 x}

0 < x < 6

Interval Notation

(0, 6)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 6

Find undefined (singularity) points:

x = 0, x = 6

Combine real regions and undefined points for final function domain

0 < x < 6

\frac{3 - x + 1}{x + 1 - 1}

f (x) = ln (x^{2} + 3 x)

f (x) = 0. 3^{x}

y = \frac{6}{x ( x + 9 )}

f (x) = \frac{2 x}{( x + 4 ) ( x - 9 )}

What is the domain of f(x)= 1/(sqrt(-x^2+6x)) ?
The domain of f(x)= 1/(sqrt(-x^2+6x)) is 0<x<6