What is the domain of y=(2x+1)/(x^2+x-2) ?

The domain of y=(2x+1)/(x^2+x-2) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(2x+1)/(x^2+x-2)

domain

y = \frac{2 x + 1}{x ^{2} + x - 2}

x < - 2 or - 2 < x < 1 or x > 1

Interval Notation

(- \infty, - 2) \cup (- 2, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 2

The function domain

x < - 2 or - 2 < x < 1 or x > 1

f (x) = \frac{5}{- x + 2}

f (x) = 2 x - 5

\frac{y + 8}{y ^{2} - 3 y + 2}

f (x) = \frac{1}{x ^{2}} - 1

f (x) = \frac{6 x ^{2} + x - 5}{3 x ^{2} - 7 x - 20}

What is the domain of y=(2x+1)/(x^2+x-2) ?
The domain of y=(2x+1)/(x^2+x-2) is x<-2\lor-2<x<1\lor x>1