What is the domain of f(x)=sqrt(x)*sqrt(4-x^2) ?

The domain of f(x)=sqrt(x)*sqrt(4-x^2) is 0<= x<= 2

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domain of f(x)=sqrt(x)*sqrt(4-x^2)

domain

f (x) = x \cdot 4 - x^{2}

0 \leq x \leq 2

Interval Notation

[0, 2]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 2

The function domain

0 \leq x \leq 2

f (x) = \frac{x + 3}{ln ( x - 1 )}

\frac{4}{x + 1}

f (x) = - x^{2} + 2 x + 1

2 x^{2} - 7 x - 6

f (x) = ln (64 - x^{2})

What is the domain of f(x)=sqrt(x)*sqrt(4-x^2) ?
The domain of f(x)=sqrt(x)*sqrt(4-x^2) is 0<= x<= 2