What is the domain of sqrt(x^2+x-6) ?

The domain of sqrt(x^2+x-6) is x = 2

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domain of sqrt(x^2+x-6)

domain

x^{2} + x - 6

x \leq - 3 or x \geq 2

Interval Notation

(- \infty, - 3] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 2

The function domain

x \leq - 3 or x \geq 2

arcsin (\frac{x - 2}{3})

f (x) = \frac{x + 5}{x - 8}

f (x) = 5 x - 7 + 3

f (x) = 2 - ∣ x - 3 ∣

f (x) = \frac{x ^{3} - x ^{2} + x}{x}

What is the domain of sqrt(x^2+x-6) ?
The domain of sqrt(x^2+x-6) is x<=-3\lor x>= 2