What is the domain of f(x)= 1/(\sqrt[4]{9-x^2)} ?

The domain of f(x)= 1/(\sqrt[4]{9-x^2)} is -3<x<3

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domain of f(x)= 1/(\sqrt[4]{9-x^2)}

domain

- 3 < x < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x < 3

f (x) = 5 x^{3} - 5 x + 1

x^{4} - 4 x^{3} + \frac{14}{3} x^{2} - \frac{9}{7} x + 2

y = - 2 (3 x)^{\frac{1}{6}}

arcsin (ln (\frac{x}{3}))

f (x) = \frac{12 + x - x ^{2}}{∣ 2 x - 5 ∣}

What is the domain of f(x)= 1/(\sqrt[4]{9-x^2)} ?
The domain of f(x)= 1/(\sqrt[4]{9-x^2)} is -3<x<3