What is the domain of f(x)=\sqrt[3]{y/(y-6)} ?

The domain of f(x)=\sqrt[3]{y/(y-6)} is y 6

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domain of f(x)=\sqrt[3]{y/(y-6)}

domain

y < 6 or y > 6

Interval Notation

(- \infty, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

y = 6

The function domain

y < 6 or y > 6

f (x) = x^{3} - 9 x

2 x^{2} - 3 x - 2

f (x) = \frac{8 - x ^{2}}{3}

y = 8

f (x) = 20 x

What is the domain of f(x)=\sqrt[3]{y/(y-6)} ?
The domain of f(x)=\sqrt[3]{y/(y-6)} is y<6\lor y>6