What is the domain of y=sqrt(2x+16) ?

The domain of y=sqrt(2x+16) is x>=-8

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domain of y=sqrt(2x+16)

domain

y = 2 x + 16

x \geq - 8

Interval Notation

[- 8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

The function domain

x \geq - 8

\frac{x ^{4} + 1}{x ^{2}}

f (x) = lo g_{10} (\frac{3}{9 - x ^{2}})

f (x) = (\frac{1}{2})^{x + 3} - 4

f (x) = (x + 1)^{3}