What is the domain of f(x)= 1/(sqrt(-x^2+4x)) ?

The domain of f(x)= 1/(sqrt(-x^2+4x)) is 0<x<4

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domain of f(x)= 1/(sqrt(-x^2+4x))

domain

f (x) = \frac{1}{- x ^{2} + 4 x}

0 < x < 4

Interval Notation

(0, 4)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 4

Find undefined (singularity) points:

x = 0, x = 4

Combine real regions and undefined points for final function domain

0 < x < 4

f (x) = arcsin (2 x + 1)

f (x) = \frac{x ^{2}}{( x - 1 )}

f (x) = x + 3 + 3

f (x) = x^{3} - 5 x^{2} + 2 x + 8

\frac{3}{x ^{2} - 1}

What is the domain of f(x)= 1/(sqrt(-x^2+4x)) ?
The domain of f(x)= 1/(sqrt(-x^2+4x)) is 0<x<4