What is the domain of f(x)= 1/(x^2-1)-3 ?

The domain of f(x)= 1/(x^2-1)-3 is x 1

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domain of f(x)= 1/(x^2-1)-3

domain

f (x) = \frac{1}{x ^{2} - 1} - 3

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

\frac{x ^{2} - 9}{x ^{2} - 4}

f (x) = \frac{1 - x}{x - 3}

f (x) = 4^{x + 1}

f (x) = \frac{4 - x}{x ^{2} - 16}

f (x) = 19

What is the domain of f(x)= 1/(x^2-1)-3 ?
The domain of f(x)= 1/(x^2-1)-3 is x<-1\lor-1<x<1\lor x>1