What is the domain of f(x)=sqrt(2x^2-x-6)+2 ?

The domain of f(x)=sqrt(2x^2-x-6)+2 is x = 2

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domain of f(x)=sqrt(2x^2-x-6)+2

domain

f (x) = 2 x^{2} - x - 6 + 2

x \leq - \frac{3}{2} or x \geq 2

Interval Notation

(- \infty, - \frac{3}{2}] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{2} or x \geq 2

The function domain

x \leq - \frac{3}{2} or x \geq 2

f (x) = \frac{x}{ln ( x )}

f (x) = \frac{( - 1 )}{x}

f (x) = 5 - 2 x + 4

f (x) = 2 - \frac{x}{x - 1}

∣ x + 4 ∣

What is the domain of f(x)=sqrt(2x^2-x-6)+2 ?
The domain of f(x)=sqrt(2x^2-x-6)+2 is x<=-3/2 \lor x>= 2