What is the domain of f(x)=sqrt(5+ln(x)) ?

The domain of f(x)=sqrt(5+ln(x)) is x>= 1/(e^5)

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domain of f(x)=sqrt(5+ln(x))

domain

f (x) = 5 + ln (x)

x \geq \frac{1}{e ^{5}}

Interval Notation

[\frac{1}{e ^{5}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{5}}

The function domain

x \geq \frac{1}{e ^{5}}

f (x) = \frac{2}{3 ^{3} - 4 x}

\frac{x - 1}{x + 5}

f (x) = ∣ x - 4 ∣ + 2 x - 6

- 8 + \frac{1}{2} x

f (x) = \frac{ln ( x - 2 ) + ln ( 7 - x )}{x - 5}

What is the domain of f(x)=sqrt(5+ln(x)) ?
The domain of f(x)=sqrt(5+ln(x)) is x>= 1/(e^5)