What is the domain of f(x)=sqrt(4/5 x+2) ?

The domain of f(x)=sqrt(4/5 x+2) is x>=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(4/5 x+2)

domain

f (x) = \frac{4}{5} x + 2

x \geq - \frac{5}{2}

Interval Notation

[- \frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{5}{2}

The function domain

x \geq - \frac{5}{2}

f (x) = lo g_{10} (1 - x^{2})

9 x - 5

d (y) = y + 3

y = 3 x - 8

y = 2^{- x}

What is the domain of f(x)=sqrt(4/5 x+2) ?
The domain of f(x)=sqrt(4/5 x+2) is x>=-5/2